Wednesday, November 21, 2012
GEOGRAPHY, MECHANICAL SHOP THEORY & PRACTICE, and MATHEMATICS: Arc length, radius, central angle, Angular displacement, velocity
S = rt
where:
S = arc length
r = radius
t = central angle, radians
Applications: Latitude & Longitude
LATITUDE
Latitude is the angle measured at the Earth's center between a point on the Earth and the equator
LONGITUDE
Longitude is the angle between the meridian passing through a point on the Earth, and the prime meridian passing through Greenwich, England
MERIDIAN
A Meridian is an imaginary circle passing through any point on the Earth's surface and through the North and South poles
Example Problem:
A city has a latitude of 45 N. The Earth has a radius of 4000 miles. Determine how many miles north of the equator the city is.
find:
S = distance of the city North from the equator
given:
r = 4000 miles
t = 45 degrees
solution:
S = rt
S = 4000 * 45 * pi/180
S = 4000 * 45 * 3.1416/180
S = 3,142 miles
Applications: Gears, Pulleys, Rack & Pinion
Example Problem:
A rack and pinion assembly rotates 240 degrees. How far will the rack move if the pitch diameter is 24 in.
find:
S = distance the rack moved
given:
r = 24/2
r = 12 in
t = 240 degrees
solution:
t = 240 * pi/180
t = 240 * 3.1416/180
t = 4.19 radians
S = rt
S = 12 * 4.19
S = 50.3 in
Example Problem:
Three pulleys of the same diameters of 6 in are arranged such that a right triangle with sides 5, 12, 13 ft is formed. Calculate the length of the belt around the pulleys.
find:
L = length of the belt around the pulleys
given:
d = 6 in
d = 6 in * 1 ft/12 in
d = 0.5 ft
solution:
The total curved portion of the belt is equal to the circumference of one pulley, Lc
Lc = pi * d
Lc = 3.1416 * 0.5
Lc = 1.57 ft
the (total) length of the belt around the pulleys
L = Lc + 5 + 12 + 13
L = 1.57 + 5 + 12 + 13
L = 31.57 ft
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ANGULAR DISPLACEMENT & ANGULAR VELOCITY
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Sa = wt
where:
Sa = angular displacement
w = angular velocity in degrees, radians, revolutions per unit time
t = time
Example Problem:
A wheel is rotating with angular velocity of 2400 rpm (revolutions per minute). Find how many revs does it make in 4 seconds.
find:
Sa = angular displacement
given:
w = 2400 rev/min * 1 min/60 sec
w = 40 rps (rev/sec)
t = 4 sec
solution:
Sa = wt
Sa = 40 rev/sec * 4 sec
Sa = 160 revs
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